[math]\frac{\left(y+2\right)^2}{9}-\frac{\left(x-1\right)^2}{1}=1[/math][br][br]Horizontal or Vertical?[br]This Hyperbola is Vertical, the leading term is y.[br][br]Center:[br](1,-2), be careful to take the y value from y and the x value from x, regardless of the order.[br][br]Vertices: since b is 3, and this is vertical,[br](1,1) and (1,-5)[br][br]Foci:[br]Using [math]c^2=a^2+b^2[/math], [math]c=\sqrt{10}[/math][br]so the foci are [math]\left(1,-2+\sqrt{10}\right)[/math] and [math]\left(1,-2-\sqrt{10}\right)[/math][br]Or approximately[math]\left(1,1.16\right)[/math] and [math]\left(1,-5.16\right)[/math][br][br]If you use the tools above, you can find this is true