Proof: Assume that Axiom 1 is dependent on the other affine axioms. Let [math]a[/math] be parallel to [math]b[/math]. Affine Axiom 4 tells us that there are three non-collinear points, [math]A,B,C[/math]. Affine Axiom 2 tells us that any two distinct points have exactly one line in common. Affine Axiom 3 tells us that any point not on a line l lies on exactly one line not intersecting l. Consider [math]C[/math] on [math]b[/math]. Since [math]a\parallel b[/math], we know Axiom 3 is satisfied. However, notice that the diagram above satisfies Axioms 2,3, and 4, but does not satisfy Affine Axiom 1 which says a line lies on at least two points. Therefore, by contradiction, we have shown that Affine Axiom 1 is independent from the other affine axioms. [math]\diamondsuit[/math]

Proof: Assume that the affine axioms are dependent on one another. Axiom 4 tells us that there exists a set of three non-collinear points. Consider points [math]A,B,[/math] and [math]C[/math]. Axiom 3 tells us that any point not on a line lie on exactly one line not intersecting that line. That means that there are lines [math]\overline{AB}[/math] and through [math]C[/math]. Axiom 1 tells us that a line lies on at least two points. Point [math]D[/math] on the line through [math]C[/math] accommodates this axiom. However, notice that there does not exist exactly one line through any two distinct points. Therefore, Axiom 2 is independent from the other three affine axioms. [math]\diamondsuit[/math]

Proof: Assume that the axioms are dependent on one another. Affine Axiom 4 tells us that there are three non-collinear points, [math]A,B[/math]and [math]C[/math]. Axiom 2 tells us that there is exactly one line through any two distinct points. This is seen in [math]a,b[/math] and [math]c[/math]. These lines also follow Affine Axiom 1 which says that a line lies on at least two points. However, note that there is not a line through [math]C[/math] parallel to [math]a[/math]. Therefore, Affine Axiom 3 is independent of the other axioms. [math]\diamondsuit[/math]

Proof: Assume that the affine axioms are dependent on each other. Axiom 3 tells us that there exists a point [math]C[/math] not on line [math]\overline{AB}[/math] that lies on exactly one line [math]\overline{CD}[/math] not intersecting [math]\overline{AB}[/math]. This follows Affine Axiom 1 because a line lies on at least two points. This also follows Affine Axiom 2 because any two distinct points have exactly one line in common. However, notice that there are four points in this sketch in order to satisfy all three of these axioms. This contradicts Affine Axiom 4 which states that there are three non-collinear points because points [math]C,D,E[/math] all lie on one line, [math]b[/math]. Therefore, Axiom 4 is independent of the other axioms.[math]\diamondsuit[/math]