Select the definition type (Weierstrass / Neighbourhoods)[br]Move the slider M to view how the neighbourhoods involved in the definition change accordingly.[br]Move x to view the corresponding values of f(x) in the interval in which the limit is satisfied.

The line [math]x=x_0[/math] is then ......[br][br]Apply the definition and state which of the following limits are correct:[br][br][math]\displaystyle{\lim_{x \to 0^+}(e^\frac{1}{x}) = +\infty}[/math][br][br][math]\displaystyle{\lim_{x \to 2^+}log(x^2-4) = +\infty}[/math][br][br][math]\displaystyle{\lim_{x \to +0}log \frac{1}{x^2} = +\infty}[/math]