Polygon Angle Sum

This demonstrates that the angle sum is 180[sup]o[/sup] times the number of triangles, which is 2 less than the number of sides. 180[sup]o[/sup] (n – 2)
Polygon Angle Sum #1
This demonstrates that the angle sum is 360[sup]o[/sup] less than 180[sup]o[/sup] times the number of triangles drawn from the center. 180[sup]o[/sup] n – 360[sup]o[/sup]
Polygon Angle Sum #2

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