CCGPS CA 1.5.1 Example 3

Solve the equation for [i]y[/i].

[list=1] [*]Begin isolating [i]y[/i] by adding or subtracting constants. [*]To further isolate [i]y[/i], divide both sides of the equation by the coefficient of [i]y[/i]. [/list] This applet is provided by Walch Education as supplemental material for the [i]CCGPS Coordinate Algebra[/i] program. Visit [url="http://www.walch.com"]www.walch.com[/url] for more information on our resources.

CCGPS CA 1.5.1 Example 4

The formula for finding the area of a triangle is [math]A = \frac{1}{2}bh[/math] , where [i]b[/i] is the length of the base and [i]h[/i] is the height of the triangle. Suppose you know the area and height of the triangle, but need to find the length of the base. In this case, solving the formula for [i]b[/i] would be helpful.

[list=1] [*]Begin isolating [i]b[/i] by multiplying both sides of the equation by the reciprocal of [math]\frac{1}{2}[/math], or 2. [*]To further isolate [i]b[/i], divide both sides of the equation by [i]h[/i]. [*]The formula for finding the length of the base of a triangle can be found by doubling the area and dividing the result by the height of the triangle. [/list] This applet is provided by Walch Education as supplemental material for the [i]CCGPS Coordinate Algebra[/i] program. Visit [url="http://www.walch.com"]www.walch.com[/url] for more information on our resources.

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