Recall that the measure of an arc of a circle is the same as the measure of its corresponding central angle. (See applet.)[br][br]Click on the first [color=#b20ea8]pink checkbox[/color] to show just [color=#b20ea8]1 inscribed angle[/color] that intercepts [color=#0a971e]arc AB[/color]. [br]Notice, in the applet below, how the [color=#b20ea8]inscribed angle[/color] and central angle (angle AOB) both intercept the [color=#0a971e]same arc[/color].[br][br]Use the inscribed angle theorem you've just learned (from http://tube.geogebra.org/m/1473237) help you see a second corollary that easily provable from this theorem. Be sure to move points [color=#1551b5]A[/color], [color=#1551b5]B[/color], and the [color=#b20ea8]pink vertices of all the inscribed angles you see[/color] around as well. (You can also change the radius of the circle if you wish.)[br][br][b]Complete the following corollary: In a circle, if 2 or more [color=#b20ea8]inscribed angles[/color] intercept the [color=#0a971e]SAME ARC[/color], then...[/b]

Activity & question are contained in the description above the applet.