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8^x=1/64
By the equations for logarithm definition we have that
[color=#0a971e]x[/color]=log[color=#c51414]8[/color](1/64)=log[color=#c51414]8[/color](1)-log[color=#c51414]8[/color](8^2)=-2*log[color=#c51414]8[/color](8)=[color=#0a971e]-2[/color]