Angle Bisector Proportionality Theorem
What is ray AE?
Altitude
Angle Bisector
Perpendicular Bisector
Median
Compare the ratios [math]\frac{AB}{BE}[/math]and [math]\frac{AC}{CE}[/math].
[math]\frac{AB}{BE}[/math]<[math]\frac{AC}{CF}[/math]
[math]\frac{AB}{BE}[/math]=[math]\frac{AC}{CF}[/math]
[math]\frac{AB}{BE}[/math]>[math]\frac{AC}{CF}[/math]
Drag point C. Do the ratios still have the same relationship?
Yes
No
[br]
Solve for x
5
3.2
80
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Information: Angle Bisector Proportionality Theorem
