Pythagoras' Theorem with animation

This is an alternative proof of Pythagoras' Theorem. Change the size of the triangle and animate to see the proof in action.

What determines the position of the lines dividing the bottom square?

Graphical solution of simultaneous equations

1. Rearrange the equations into the form y = mx + c 2. Think where those lines are on the grid 3. Move the Point P to where you think the lines cross each other 4. Reveal the lines and distance from P to I 5. Record the solution and distance for each question

Can you keep your distance reducing? Can you get an average distance below 2 or 1 even? Can you make up a set of simultaneous equations that have no solution?

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