The area of the cell consists of 6 trapezoids and 3 rhombusses.[br]We write the area as a function of x = the length of the segment |BB[sub]1[/sub]|.

The total area of the cell = 3 . (area rhombus) + 6 . (area trapezoid)[br][br]A(x)= 3 . [math]\frac{\sqrt{3}.r.\sqrt{4x^2+r^2}}{2}[/math] + 6 . [math]r.\frac{2h-x}{2}[/math]