The Nucleus of the Problem
Notes: -Regular metric space. -P is free. -One point scales and rotates the coordinate space about an origin. The tesselation must include P. Here is a simple [b]Procedure:[/b] -Each pair of circles intersects in two points. One is common to all three, at point P. The remaining three (one from each pair) are free. -Intersect a new, neighboring circle at one such duplicate point. -For two given circles to share a [i]unique[/i] moving point, we must now skip over this common intersection. -But we now have two new intersections, shared with the neighbor. -Each of these is a new moving point. That is all.