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Ch 5 geo
- The midsegments divide any triangle in congruent triangles
- Perpendicular Bisectors in a Triangle
- Perpendicular Bisectors in a Triangle
- Perpendicular Bisectors in a Triangle
- Angle Bisectors in a triangle
- Angle Bisector/Opposite Side
- Triangle-Angle Bisector Theorem
- Angle Bisector in a Triangle Similarity
- Medians of a Triangle
- Medians In a Triangle
- Altitudes in a triangle
- Explore circumcenters, incenters, centroids and orthocenters
- The Points of Concurrency of a Triangle
- Centers of a Triangle
- Euler Line Generator
- The Euler Line of a Triangle
- Triangle Inequality Theorem
- Triangle Inequality (II)
- Inequalities in 1 Triangle
- Side-Angle-Side Inequalities In Two Triangles
- Inequalities in Two Triangles-Hinge Theorem
- Similar Triangles Task 2
- Altitudes of a Triangle Investigation
- Partition Calculator
- Circumcenter of a Triangle
- Incenter
- Orthocenter
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Ch 5 geo
Deidra Baker, Oct 19, 2017
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1. The midsegments divide any triangle in congruent triangles
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2. Perpendicular Bisectors in a Triangle
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3. Perpendicular Bisectors in a Triangle
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4. Perpendicular Bisectors in a Triangle
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5. Angle Bisectors in a triangle
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6. Angle Bisector/Opposite Side
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7. Triangle-Angle Bisector Theorem
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8. Angle Bisector in a Triangle Similarity
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9. Medians of a Triangle
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10. Medians In a Triangle
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11. Altitudes in a triangle
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12. Explore circumcenters, incenters, centroids and orthocenters
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13. The Points of Concurrency of a Triangle
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14. Centers of a Triangle
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15. Euler Line Generator
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16. The Euler Line of a Triangle
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17. Triangle Inequality Theorem
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18. Triangle Inequality (II)
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19. Inequalities in 1 Triangle
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20. Side-Angle-Side Inequalities In Two Triangles
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21. Inequalities in Two Triangles-Hinge Theorem
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22. Similar Triangles Task 2
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23. Altitudes of a Triangle Investigation
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24. Partition Calculator
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25. Circumcenter of a Triangle
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26. Incenter
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27. Orthocenter
The midsegments divide any triangle in congruent triangles
A midsegment of a triangle is a segment that connects the midpoints of any two sides of the triangle.
This applet demonstrates that the three midsegments of any triangle divide the original triangle in four congruent triangles.
The demonstration is based on the following properties:
1.The midsegment is always parallel to the third side of the triangle.
2. Any parallelogram has a rotational symmetry with center the intersection point of the diagonals and angle of rotation .
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