Jean Monnet hexagonal design -Andrei
1.
The area of a red triangle AMP is:
2
[math]\frac{\sqrt{3}}{4}[/math]
[math]\sqrt{3}[/math]
[math]\frac{\sqrt{3}}{2}[/math]
2.
OFQN is
parallelogram
square
rectangle
rhombus
3.
The area of the quadrilateral OFQN is:
[math]\frac{\sqrt{3}}{2}[/math]
[math]\frac{3\sqrt{3}}{2}[/math]
[math]2\sqrt{3}[/math]
[math]\frac{\sqrt{3}}{4}[/math]
4.
Find the blue area.
[math]A=A_{hexagon}-A_{red}[/math][br]Use the area of the hexagon [math]A_6=\frac{3l^2\sqrt{3}}{2}[/math]
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Information: Jean Monnet hexagonal design -Andrei