[justify] Multiplica-se a primeira fração pela fração inversa da segunda.[br][br][color=#6d9eeb]Ex. 01[/color] - [math]\frac{5a^2b^2}{2xy}\div\frac{2ab}{3xy}=\frac{5a^2b^2}{2xy}\times\frac{3xy}{2ab}=\frac{15ab}{4}[/math][br][br][color=#6d9eeb]Ex. 02[/color] - [math]\frac{x^2-xy}{y}\div\frac{x^2-y^2}{xy}=\frac{x^2-xy}{y}\times\frac{xy}{x^2-y^2}=\frac{x\left(x-y\right)}{y}\times\frac{xy}{\left(x+y\right)\left(x-y\right)}=\frac{x}{1}\times\frac{x}{\left(x+y\right)}=\frac{x^2}{x+y}[/math][br][br][color=#6d9eeb]Ex. 03[/color] - [math]\frac{a+b+ax+bx}{ax+bx}\div\frac{x^2-1}{x^2-x}=\frac{1\left(a+b\right)+x\left(a+b\right)}{x\left(a+b\right)}\div\frac{\left(x+1\right)\left(x-1\right)}{x\left(x-1\right)}=\frac{\left(a+b\right)\left(x+1\right)}{x\left(a+b\right)}\times\frac{x\left(x-1\right)}{\left(x+1\right)\left(x-1\right)}=1[/math][/justify]