[math]\left(2+3\right)\left(4\right)[/math]
[math]2-\left(3+4\right)[/math]
Expand to create an equivalent expression that uses the fewest number of terms:[br] [math]\left(\left(\left(\left(x+1\right)\frac{1}{2}\right)+1\right)\frac{1}{2}\right)+1[/math]. If we wrote a new expression following the same pattern so that there were 20 sets of parentheses, how could it be expanded into an equivalent expression that uses the fewest number of terms?