Review of Linear Equations in One Variable

Overview
This is a review guide for your upcoming Knowledge Check on Linear Equations in One Variable. This review was created for your study purposes only and will not count toward your final grade.
1
Solve the equation.[br][br][math]4d+2=6[/math]
2
Solve the equation.[br][br][math]-7c=-3c-8[/math]
3
Solve the equation.[br][br][math]\frac{b}{3}+1=0[/math]
4
Solve the equation.[br][br][math]-3p+7=5p+1[/math]
5
Solve the equation.[br][br][math]4a-9=3\left(a-3\right)[/math]
6
Solve the equation.[br][br][math]3\left(2c+5\right)=-2\left(c-8\right)[/math]
7
Solve the equation.[br][br]7b+3(b-1)+3=2(b+8)
8
Solve the equation.[br][br][math]\frac{x}{8}-\frac{1}{4}=\frac{1}{2}[/math]
9
Solve the equation.[br][br][math]\frac{x+5}{2}-\frac{2x+10}{9}=5[/math]
10
Solve the equation.[br][br][math]\frac{x-6}{3}-\frac{2x+8}{2}=12[/math]
11
Solve the equation.[br][br][math]\frac{1}{10}p-3=\frac{2}{5}p[/math]
12
Solve the equation[br][br][math]-\frac{1}{4}\left(2-3t\right)=\frac{3}{4}[/math]
13
Solve the equation.[br][br][math]\frac{2}{7}\left(w+4\right)=\frac{1}{2}[/math]
14
Solve the equation[br][br][math]\frac{1}{4}y-\frac{3}{4}=\frac{1}{2}y+1[/math]
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Information: Review of Linear Equations in One Variable