[math](x-5)^2=\text{-}1[/math]
[size=150]For which values of[math]a[/math] does the equation [math]x^2-8x+a=0[/math] have two real solutions? One real solution? No real solutions? Explain your reasoning.[/size]
[math]f(x)=x^2-8x+13[/math][br][math]g(x)=x^2-8x+16[/math][br][math]h(x)=x^2-8x+19[/math]