Vary the degree of the Maclaurin polynomial to see how it converges with the graph of ln([i]x[/i]+1) between [i]x[/i]=-1 and [i]x[/i]=1.[br]The calculation shows the difference between ln([i]x[/i]+1) and the Maclaurin approximation. You can see how this diverges rapidly when [i]x[/i] is outside the interval.