[i]Azim runs along a straight line from a fixed point [/i][math]O[/math][i]. The velocity of Azim's run, [/i][math]v[/math][math]kmj^{-1}[/math][i][br]at a [/i][math]t[/math][i] time of hours after passing [/i][math]O[/math][i] is given by [/i][math]v=mt^2+nt[/math][i] . Azim stops to rest after running half the distance at [/i][math]t=1[/math][i] with an acceleration of 12.5 [/i][math]kmj^{-2}[/math][i][br]12.5. Find[br][Consider movement to the right is positive][/i][br][br][i](a) the value of m and the value of n,[/i]

[i](b) The maximum velocity, in [/i][math]kmj^{-1}[/math][i] , of Azim's run,[/i]

[i](c) the distance, in [/i][math]km[/math][i] , travelled by Azim in the second hour.[/i]