Shear-Moment (V-M) Diagrams: Simply Supported Beam

Point Loads

Use the interactive Figure below to determine the shear and moment diagrams for the simply supported beam.[br][br]Click and drag the red dot to move the location of point load on the beam. Use the slider to change its magnitude and direction.[br][br]Use the Figure to answer the following questions.[br]

Increasing the magnitude of the point load has what impact on the shear and moment diagram?

Decreases [math]V_{max}[/math]and[math]M_{max}[/math] It has no effect on either Increases [math]V_{max}[/math]and[math]M_{max}[/math] Increases [math]V_{max}[/math]only

Why does the shear remain constant between the supports and point load?

The intensity of the distributed load is zero between them The support reactions are constant The slope of the shear diagram is always constant

Where should the point load be located along the beam in order for the moment to be maximized?

At support B At the midspan of the beam At support A Halfway between the midspan and B Halfway between A and the midspan

Moving the location of the point load along the beam without changing its magnitude has what impact on the moment diagram?

It shifts the location of [math]M_{max}[/math] It has no impact on the moment diagram It causes its shape to change to a parabolic curve It causes it to change sign

Distributed Loads

Use the interactive Figure below to determine the shear and moment diagrams for the simply supported beam with a distributed load.[br][br]Click and drag the red dots to change the magnitude and shape of the distributed load on the beam. [br][br]Use the Figure to answer the following questions.[br]

For a beam with a uniformly distributed load, what effect will an increase in the magnitude of the distributed load have on the shear diagram?

It will change the shape of the shear curve It will have no impact It will change the location of the maximum shear It will decrease the magnitude of the maximum shear It will increase the magnitude of the maximum shear

How will the shape of the shear curve change if the distributed load changes from uniform (rectangular) to a uniformly varying (triangular) distributed load?

It changes from parabolic to linear It changes from linear to cubic It changes from linear to parabolic It won't change at all

What affect will changing the distributed load from rectangular to triangular have on the shape of the bending moment curve?

It will change from parabolic to cubic It won't change at all It will change from linear to parabolic It will change from cubic to parabolic

As the distributed load changes from a triangular load starting at [i]w[sub]a[/sub][/i] = 0, to a rectangular load of the same magnitude as [i]w[sub]b[/sub][/i], what do you expect will happen to the location where the shear force changes sign? [br][br][br]

It will remain unchanged It will move toward B It will move toward the midspan of the beam

For a triangular distributed load starting at[i] w[/i][sub][i]a[/i] [/sub]= 0, at which support will the slope in the shear curve be greater, why?

Support A, because [i]w[/i] starts increasing at A Neither Both will have the same slope Support B, because the intensity of [i]w[/i] is greatest at B Support B, because B[sub]y[/sub] is greater than A[sub]y[/sub]

Shear-Moment (V-M) Diagrams: Simply Supported Beam

Point Loads

Distributed Loads

Information: Shear-Moment (V-M) Diagrams: Simply Supported Beam