[size=150][b][u][color=#0000ff]PART A (RIGHT TRIANGLES)[br]DIRECTIONS:[/color][/u][/b][/size][br][br]In Part A, you will use the moving and additivity principles to explain in three ways why the following right triangle has area [math]\frac{1}{2}\left(b\cdot h\right)[/math]
Explain how the demonstration above shows that the area of a triangle is [math]\frac{1}{2}\left(b\cdot h\right)[/math]. Be sure to mention any principles of area helpful to your explanation.
Use the demonstration above to explain why the area of a triangle can also be thought of as [math]\left(\frac{1}{2}b\right)\cdot h[/math]. Be sure to mention any principles of area helpful to your explanation.
Use the demonstration above to explain why the area of a triangle can also be thought of as [math]b\cdot\left(\frac{1}{2}h\right)[/math]. Be sure to mention any principles of area helpful to your explanation.
[u][color=#0000ff][b][size=150]PART B (ACUTE TRIANGLES)[br]DIRECTIONS:[/size][br][/b][/color][/u][br][size=100]In Part B, you will use the moving and additivity principles to explain in two ways why the acute triangle below has area [math]\frac{1}{2}\left(b\cdot h\right)[/math][/size]
Use the demonstration above to explain why the area of a triangle can also be thought of as [math]b\cdot\left(\frac{1}{2}h\right)[/math]. Be sure to mention any principles of area helpful to your explanation.
Use the demonstration above to explain why the area of a triangle can also be thought of as [math]\frac{1}{2}\left(b\cdot h\right)[/math]. Be sure to mention any principles of area helpful to your explanation.
[b][u][color=#0000ff]PART C (OBTUSE TRIANGLES)[br]DIRECTIONS:[/color][/u][/b][br][br]Now, we will apply what we know about right triangles in order to prove the formula for the area of an obtuse triangle is also [math]\frac{1}{2}\left(b\cdot h\right)[/math]
Use the figure above AND what you know about right triangle areas to prove that the area of the purple obtuse triangle is also [math]\frac{1}{2}\left(b\cdot h\right)[/math]