Construct a perpendicular line segment from one vertex to the base of the triangle. Calculate the length of the base and of the height to determine the area of the triangle using [math]A=\frac{1}{2}b\cdot h[/math].
A = 63
Method 2
Calculate the length of all three sides and use Heron's formula, [math]A=\sqrt{s\cdot\left(s-a\right)\cdot\left(s-b\right)\cdot\left(s-c\right)}[/math], where s is the semiperimeter, [math]s=\frac{a+b+c}{2}[/math], of the triangle. Did you get the same answer?
A = 63
Method 3
Calculate the measure of any angle using the Law of Cosines, [math]cosA=\frac{b^2+c^2-a^2}{2bc}[/math], and then use the formula, derived from right triangle trigonometry, [math]A=\frac{1}{2}b\cdot c\cdot sinA[/math]. You can use any pair of sides and their included angle. Did you get the same result?
A = 63
Method 4
Calculate the determinant of the matrix formed by entering the coordinates of points followed by the number 1, as in the image above, in a 3 X 3 matrix.[br]If it is positive, multiply it by[math]\frac{1}{2}[/math] and if it is negative, by [math]-\frac{1}{2}[/math]. Did you get the same result?
A = 63
Method 5
Construct a rectangle in which the triangle is inscribed. Calculate the areas of the right triangles outside the triangle and subtract them from the area of the rectangle.
A = 156 - 39 - 24 - 30 = 63
Extension to 3-dimensions
Which of the methods above would apply to a triangle in 3-dimensions?
Heron's formula, [math]A=\frac{1}{2}bh[/math], [math]A=\frac{1}{2}b\cdot c\cdot sin\left(A\right)[/math], constructing a circumscribed rectangle.
Find the area using the methods you indicated.
Magnitude of the Cross-Product
Find the vector that is perpendicular to the plane containing the triangle. [br][img]blob:https://www.geogebra.org/9046c906-7db7-47c2-a545-5d76471e3796[/img][br]The area of the triangle is 1/2 the magnitude of this vector.