Constant Times, Sum/Diff Rules

Derivative of k times a function is k times derivative of the function. Thus[br] [math]\frac{d}{dx}\left(kf\left(x\right)\right)=k\frac{d}{dx}\left(f\left(x\right)\right)[/math][br]Sum/Difference of the derivative of two functions is sum/difference of the derivatives of the two functions. Thus [br] [math]\frac{d}{dx}\left(f\left(x\right)\pm g\left(x\right)\right)=\frac{d}{dx}\left(f\left(x\right)\right)\pm\frac{d}{dx}\left(g\left(x\right)\right)[/math][br][br]These two rules show that the process of finding derivatives is linear. Namely,[br][br] [math]\frac{d}{dx}\left(kf\left(x\right)+lg\left(x\right)\right)=k\frac{d}{dx}\left(f\left(x\right)\right)+l\frac{d}{dx}\left(g\left(x\right)\right)[/math][br][br]The purpose of this applet is to facilitate practice of this rule.

Product Rule of Differentiation

Purpose of this applet is to provide practice on product rule of differentiation, which is [br][math]\left(uv\right)'=u'v+uv'[/math][br]An example is given for help. There are plenty of questions for practice. Follow the instructions which can be viewed by checking the checkbox Instructions.

Chain Rule With One Inner Function

This applet can be used to find derivative of a composite function generated with one inner function (composition of two functions). Enter Inner function in [i]x[/i] and outer function in [i]t[/i]. You are advised to solve the problem using pen and paper before comparing with the solution given by this applet. Please note that the simplification produced in the applet may differ from yours and may not look neat sometimes. Use this applet for practice on chain rule with one inner function.
You should have studied differentiating constant times, sum/difference, product, and quotient rules of differentiation and feel fairly comfortable with them.[br][br]For more on chain rule check my online book [br]"Flipped Classroom Calculus of Single Variable"[br]https://versal.com/learn/vh45au/

Explore Implicitely Defined Graphs

Graphs are said to be implicitely defined when their equation is not in the form [math]y=f\left(x\right)[/math] but rather in the form [math]f\left(x,y\right)=c[/math], where c may be zero.[br][br]For more on implicit differentiation check my online book [br]"Flipped Classroom Calculus of Single Variable"[br]https://versal.com/learn/vh45au/

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