IM Alg2.3.9 Practice: Solving Radical Equations

Find the solution(s) to each of these equations, or explain why there is no solution.
[math]\sqrt{x+5}+7=10[/math]
[math]\sqrt{x-2}+3=\text{-}2[/math]
For each equation, decide how many solutions it has and explain how you know.
[math](x-4)^2=25[/math]
[math]\sqrt{x-4}=5[/math]
[math]x^3-7=\text{-}20[/math]
[math]6\cdot\sqrt[3]{x}=0[/math]
[size=150]Jada was solving the equation [math]\sqrt{6-x}=\text{-}16[/math]. She was about to square each side, but then she realized she could give an answer without doing any algebra. What did she realize?[/size]
[size=150]Here are the steps Tyler took to solve the equation [math]\sqrt{x+3}=\text{-}5[/math].[br][/size][br][math]\begin{align}\sqrt{x+3} &=-5\\x+3 &=25\\x &=22\end{align}[/math][br][br]Check Tyler’s answer: Is the equation true if [math]x=22[/math]? Explain or show your reasoning.[br]
What mistake did Tyler make?[br]
Complete the table. Use powers of 16 in the top row and radicals or rational numbers in the bottom row.
[size=150]Which are the solutions to the equation [math]x^3=35[/math]?[/size]
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