A box of granola bars contains an assortment of flavors. You randomly choose a granola bar and eat it. Then you randomly choose another bar.[br][b]Event [i]A[/i]:[/b] You choose a coconut almond bar first.[br][b]Event [i]B[/i]:[/b] You choose a cranberry almond bar second.
Are event A and B dependent or independent? Justify your answer.
Event A and B are dependent. After eating one granola bar, your sample space changes and has one less option than when you chose the first granola bar.
If there are 5 Cranberry Almonds, 6 Chocolate Chip, and 4 Coconut Almond granola bars, what is the probability that you randomly choose a coconut almond bar first, and a cranberry almond bar second?
P(Coconut Almond first and Cranberry Almond second)=[math]\frac{4}{15}\cdot\frac{5}{14}=[/math][math]\frac{2}{21}[/math]
A box of granola bars contains an assortment of flavors. You randomly choose a granola bar and decide you don't want to eat that kind, so you put it back into the box. Then you randomly choose another bar.[br][b]Event [i]A[/i]:[/b] You choose a coconut almond bar first.[br][b]Event [i]B[/i]:[/b] You choose a cranberry almond bar second.
Are event A and B dependent or independent? Justify your answer.
Event A and B are independent. Since you replaced the first granola bar, the sample space is not changed after the first draw.
If there are 5 Cranberry Almonds, 6 Chocolate Chip, and 4 Coconut Almond granola bars, what is the probability that you randomly choose a coconut almond bar first, and a cranberry almond bar second?
P(Coconut Almond first and Cranberry Almond second)=[math]\frac{4}{15}\cdot\frac{5}{15}=[/math][math]\frac{4}{45}[/math]
You roll a six-sided die and flip a coin.[br][b]Event [i]A[/i]:[/b] You get a 4 when rolling the die.[br][b]Event [i]B[/i]:[/b] You get tails when flipping the coin.
Are event A and B dependent or independent? Justify your answer.
Independent; the outcome of rolling the die does not effect the outcome of flipping the coin.
What is the probability of getting a 4 when you roll the die and getting a tails when you flip the coin?
You play a game that involves spinning a wheel divided into four parts. The parts are colored blue, red, green, and yellow as shown in the picture below. Each section of the wheel has the same area.
Use a sample space to determine whether randomly spinning blue and then green are independent events.
S={blue, red, green, yellow}[br][br]The sample space does not change after the first spin, so the events are independent.
Find the probability of randomly spinning blue and then green.
P(blue first then green) = [math]\frac{1}{4}\cdot\frac{1}{4}=\frac{1}{16}[/math]
You play a game that involves spinning the money wheel shown below. You spin the wheel twice.
Find the probability that you get more than $500 on your first spin and then go bankrupt on your second spin.
The events are independent.[br]P(greater than $500 then Bankrupt) = [math]\left(\frac{5}{24}\right)\left(\frac{1}{24}\right)=\frac{5}{576}[/math]
[br]The number of species in the United States listed as endangered and threatened by category:[br][br][table][tr][td][/td][td]Endangered[/td][td]Threatened[/td][/tr][tr][td]Mammals[/td][td][center]70[/center][/td][td][center]16[/center][/td][/tr][tr][td]Birds[/td][td][center]80[/center][/td][td][center]16[/center][/td][/tr][tr][td]Other[/td][td][center]318[/center][/td][td][center]142[/center][/td][/tr][/table][br][br]
Find the probability that a randomly selected endangered species from this study is a bird.
There are 468 endangered species, of which 80 are birds.[br]P(Bird|Endangered) = [math]\frac{80}{465}=\frac{20}{117}[/math]
Find the probability that a randomly selected mammal from this study is endangered.
There are 86 mammals, of which 70 are endangered.[br]P(Endangered|Mammal) = [math]\frac{70}{86}=\frac{35}{43}[/math]
You and 19 other students volunteer are to present the “Best Teacher” award at a school banquet. One student volunteer will be chosen to present the award. Each student worked at least 1 hour in preparation for the banquet. You worked for 4 hours, and the group worked a combined total of 45 hours.
If “fair” means equally likely, identify the process that gives you a "fair" chance to be chosen. Also identify the correct probability that you are chosen.[br]
Answer will vary. One method would be to write each student's name down on a slip of paper and put them in a hat. Randomly draw one slip of paper and the student whose name is on the slip will present the award.[br]P(you are chosen) = [math]\frac{1}{20}[/math]
If “fair” means proportional to the number of hours each student worked in preparation, identify the process that gives you a "fair" chance to be chosen. Also identify the correct probability that you are chosen.
Answers will vary. One method would be to give each student one ticket for every hour they volunteered, then randomly choose a ticket. [br]P(you are chosen) = [math]\frac{4}{45}[/math]