Jumping Right In

Let's get started. Plotted below is the function[code] f(x)=x^2+2x[/code], which is the same function we were studying [url=https://www.geogebra.org/m/x39ys4d7#chapter/398514]last chapter[/url]. I've gone ahead and constructed a secant line by way of a "nudging" variable [code]h[/code]. I've also set [code]h[/code] to [code]0.01[/code]. [br][br]Therefore, the slope of the line [code]g[/code] at the point [code]A[/code] matches the function [code]f[/code] at the point [code]A[/code] [i]very[/i] closely. [br][br]Without resorting to using a limit (see last Chapter), this is about as good as we can match [code]f[/code] at point [code]A[/code]. [br][br]Type this code into the input bar to keep track of the slope of [code]g[/code] at point [code]A[/code] :[br][br][code](x(A),slope(g))[/code]
Move ahead to check that you did it correctly, and to continue the discussion.

Information: Jumping Right In