Dividing a cube by 7
[math]\frac{1}{7}+\left(\frac{1}{7}\right)^2+\left(\frac{1}{7}\right)^3+\left(\frac{1}{7}\right)^4+\left(\frac{1}{7}\right)^5+...=[/math]
[math]\frac{1}{4}[/math]
[math]\frac{1}{2}[/math]
[math]\frac{2}{7}[/math]
[math]\frac{1}{6}[/math]
[math]\frac{3}{5}[/math]
Think how can you divide a cube into 7 equal parts, all of them with the same volume and surface as well.
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