[math]7\left(c-5\right)=0[/math]
[math]x\left(2x+11\right)=0[/math]
[math]\left(x-3\right)\left(x+11\right)=0[/math]
[math]\left(x-3\right)\left(2x+11\right)=0[/math]
[math]x\left(x+3\right)\left(3x-4\right)=0[/math]
Use factors of 48 to find as many solutions as you can to the equation [math]\left(x-3\right)\left(x+5\right)=48[/math]
Once you think you have all the solutions, explain why these must be the only solutions.
[size=150]We have seen quadratic functions modeling the height of a projectile as a function of time.[br][br]Here are two ways to define the same function that approximates the height of a projectile in meters, [math]t[/math] seconds after launch:[/size][br][math]h\left(t\right)=-5t^2+27t+18[/math] [math]h\left(t\right)=\left(-5t-3\right)\left(t-6\right)[/math][br][br]Which way of defining the function allows us to use the zero product property to find out when the height of the object is 0 meters?
Without graphing, determine at what time the height of the object is 0 meters. Show your reasoning.[br]