Equation of Circle

1. 移動點P，找出P點的軌跡。

2. 點P的軌跡是一個

三角形長方形直綫圓形正方形

3. 若 r = 6, 點P(x,y)滿足以下哪條等式？

[math]\sqrt{\left(x-\left(-2\right)\right)^2+\left(y-4\right)^2}=6[/math] [math]\frac{y-4}{x-\left(-2\right)}=6[/math]

Conclusion

[size=200]Since every point on the circle satisfy the equation in Q3, the equation in Q3 is the equation of circle above.[br]因爲圓上任意點均滿足Q3的等式，所以Q3的等式就是圖中這個圓形的方程。[/size]

4. Generally, Let C(h,k) be the centre of the circle, r be the radius of the circle. Write down the equation of the circle in terms of h,k and r. 一般來説，設C(h,k)爲圓的圓心，r爲圓的半徑。試以h, k 和r 寫下圓的方程。

Equation of Circle

1. 移動點P，找出P點的軌跡。

2. 點P的軌跡是一個

3. 若 r = 6, 點P(x,y)滿足以下哪條等式？

Conclusion

4. Generally, Let C(h,k) be the centre of the circle, r be the radius of the circle. Write down the equation of the circle in terms of h,k and r. 一般來説，設C(h,k)爲圓的圓心，r爲圓的半徑。試以h, k 和r 寫下圓的方程。

Information: Equation of Circle