Berechne eine Orthonormalbasis der Eigenvektoren: [br]A={{3,2,1},{2,0,-2},{1,-2,3}}[br][br][math]T \, := \, \left(\begin{array}{rrr}-\frac{1}{\sqrt{6}}&\frac{2}{\sqrt{5}}&-\frac{\sqrt{30}}{30}\\\frac{2}{\sqrt{6}}&\frac{1}{\sqrt{5}}&\frac{\sqrt{30}}{15}\\\frac{1}{\sqrt{6}}&0&-\frac{\sqrt{30}}{6}\\\end{array}\right)[br]\\D \, := \, \left(\begin{array}{rrr}-2&0&0\\0&4&0\\0&0&4\\\end{array}\right)[br][/math]