Exercise 2.1 - Angle bisector

3 circles + 1 line = 4 steps (par 4)

Exercise 2.9 - Finding the incenter

Construct a circle inscribed in a given triangle ABC (par = 13).[br][br]10 circles + 3 lines = 13 steps.

Exercise 10.1

Exercise 2.16 - The rusty compass

4 circles + 2 lines = 6 steps (par 6)
The triangles ACD and BEF are congruent by (I.8). It follows that ABH is similar to ACD by SIM AAA, hence ABH is equilateral

Exercise - 2.24 a) - External common tangents

Ex. 2.24 a)

Exercise 4.3 - Inscribed equilateral triangle

The triangles ABD and ABC are equilateral, hence the angle ABE is 120°.[br]The angle ADF is 120°, too, since ADB is 60°.[br]Moreover the angles AFB and AEF are congruent, since they insist on the same arc. Finally AD is congruent to AB, so the triangles ADF and AEB are congruent, so AE is congruent to AF.[br][br]By construction the angle FBE is 60°, so also EAF is 60°, since they insist upon the same arc. So also the angles AEF and AFE are 60°

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