Discovering the Pythagorean Theorem Converse

Given Right [math]\Delta[/math]ABC, we want to test the Pythagorean Theorem to see if[br][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] =[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] or [br][/size][/size][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] <[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] or [br][/size][/size][br][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] >[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] [br][br]On line 1 of the input (on left), calculate c^2[br][br]On line 2, try [size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] [br][/size][/size] [br][/size][/size]
[size=200][size=150]For right triangles, [/size][/size]
[b][u][i][color=#38761d][size=200]ACTIVITY 2: [br][/size][/color][/i][/u][/b][color=#0000ff][br]Given [/color][size=200]Acute[/size][math]\Delta[/math][color=#0000ff]ABC, we want to test the Pythagorean Theorem to see if[/color][br][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] =[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] or [br][/size][/size][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] <[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] or [br][/size][/size][br][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] >[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] [br][br]On line 1 of the input (on left), calculate c^2[br][br]On line 2, try [size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] [br][/size][/size] [br]Drag the triangle around (keeping all 3 angles acute) to see if the relationship holds.[br][/size][/size]
[size=200][size=150]For acute triangles, [/size][/size]
[b][u][i][color=#38761d][size=200]ACTIVITY 3: [br][/size][/color][/i][/u][/b][color=#0000ff][br]Given [/color][size=200]Obtuse [/size][math]\Delta[/math][color=#0000ff]ABC, we want to test the Pythagorean Theorem to see if[/color][br][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] =[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] or [br][/size][/size][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] <[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] or [br][/size][/size][br][size=200] [size=150]c[sup]2[/sup][/size][sup][/sup] >[/size][size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] [br][br]On line 1 of the input (on left), calculate c^2[br][br]On line 2, try [size=100][size=150] a[sup]2[/sup] + b[sup]2[/sup] [br][/size][/size] [br]Drag the triangle around (keeping [math]\angle[/math]C obtuse) to see if the relationship holds.[br][/size][/size]
[size=200][size=150]For obtuse triangles, [/size][/size]
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情報: Discovering the Pythagorean Theorem Converse