Isometry Practice Set

Part 1: Identify the Isometry
[b]Object:[/b] A(2, 3), B(4, 3), C(4, 6)[br][b]Image:[/b] A'(5, 1), B'(7, 1), C'(7, 4)[br][b][br]Isometry:[/b] ____________________
[b]Object:[/b] P(-1, 2), Q(-3, 2), R(-3, 5)[br][b]Image:[/b] P'(1, 2), Q'(3, 2), R'(3, 5)[br][b][br]Isometry:[/b] ____________________
[b]Object:[/b] J(1, 1), K(3, 1), L(3, 4)[br][b]Image:[/b] J'(-1, 1), K'(-1, 3), L'(-4, 3)[br][b][br]Isometry:[/b] ____________________
[b]Object:[/b] S(2, 2), T(5, 2), U(5, 4)[br][b]Image:[/b] S'(5, -2), T'(8, -2), U'(8, -4)[br][b][br]Isometry:[/b] ____________________
Part 2: Find the Image Coordinates
Move triangle XYZ with vertices X(0, 0), Y(2, 4), Z(4, 0) by the vector [math]\left(-3,2\right)[/math]
Reflect L(1, 5) and M(4, 8) across the line [math]y=x[/math].
Rotate A(2, 6) [math]90^o[/math] counter-clockwise about the origin.
Reflect B(2, 3) across the x-axis, then translate it by [math]\left(\begin{matrix}4\\0\end{matrix}\right)[/math].
Part 3: Critical Thinking
If a triangle is reflected across the y-axis and then reflected again across the x-axis, which single isometry would produce the same result?
A shape is translated 2 units right and 2 units up, then reflected across the line y = x. Is the resulting transformation a Glide Reflection? Explain why or why not.
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Informazioni: Isometry Practice Set