Caso 3. Construcción de un triángulo conocido un lado y los dos ángulos adyacentes

[i]Construye el triángulo en el que un lado mide 5,34 y los ángulos adyacentes son 40[/i][i]⁰[/i][i] y 83[/i][i]⁰[/i][i].[/i][br][br]Comenzamos igual que en los dos ejemplos anteriores, utilizando la herramienta [b]Circunferencia (centro-radio)[/b] para trasladar la medida del lado conocido. Una vez dibujada la circunferencia, cualquier punto de ella determinará la medida de dicho lado.[br][br][img 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continuación, debemos trasladar la medida de los dos ángulos, para lo que utilizaremos la herramienta[br][b]Ángulo dada su amplitud[/b], de manera similar al ejemplo anterior.[br]Comenzamos por el primero de los ángulos cuya medida es de 40⁰, por lo que una vez seleccionada la herramienta, marcamos B, A e introducimos dicho valor, para obtener un nuevo punto B’ que uniremos con A con una semirrecta.[br][br][img 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continuación, repetimos el proceso para la medida del segundo ángulo que trasladamos al vértice B, por lo que seleccionamos de nuevo la herramienta Ángulo dada su amplitud, marcando A, B e introduciendo la medida de 83⁰; estableciendo el sentido horario para crear el ángulo.[br][br][img 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[/img][br][br]Obtenemos un nuevo punto A’ que uniremos con una semirrecta con B.[br][br][img 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establecido el sentido contrario para que los dos puntos A’ y B’ queden por encima del segmento AB.[br]El tercer vértice del triángulo será el punto de intersección de las dos semirrectas que obtenemos con la herramienta [b]Intersección[/b].[br]Una vez obtenido el punto C sólo queda dibujar el triángulo que tiene las medidas dadas.[br][br][img 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Information: Caso 3. Construcción de un triángulo conocido un lado y los dos ángulos adyacentes