This interactive diagram shows a simple way to obtain Archytas' solution from Archytas' triangle: given [math]a, b[/math], [math]a>b[/math], to find two mean proportionals of [math]a, b[/math], starting with Archytas' triangle with AM = [math]b[/math] and ΑΔ = [math]a[/math] (shown in the figure). Selecting K with the left button of the mouse, and moving it around the circumference, you can achieve Archytas' solution, when AMK are aligned. When moving K around the semicircle (or I along the diameter), you will see that IK is perpendicular to ΑΔ, a new circumference of diameter AI is buid and M is found intersecting the semicircle with a circle of centre A and radius [math]b[/math]. To clean the canvas and get the initial configuration displayed, click on the button with two circular arrows in the right upper corner of the canvas.