[math]\binom{2\sqrt{3}.\sqrt{3}}{4}=\binom{3\sqrt{3}}{2}cada\Delta[/math][br][math]\binom{3}{2}\sqrt{3}.4=6\sqrt{3}[/math][br][math]6\sqrt{3}=\binom{2\sqrt{3}}{2}.h[/math] h=6[br][math]a^2=\left(6\sqrt{3}\right)^2+\left(6\sqrt{3}\right)^2[/math]= [math]a=2\sqrt{39}[/math][br]área [math]\binom{6.2\sqrt{39}}{2}=6\sqrt{39}[/math][br]área total=[math]2\sqrt{39}.4=24\sqrt{39}[/math]