[size=85]Enter the values of the coefficients [b]a[/b] and [b]b[/b] of the [b][i]Transcendental function[/i][/b] and find its [b][color=#333333]Roots[/color][/b]. [br] [i]Graphical interpretation the [b]Roots[/b][/i]: the [i]intersection of implicit functions[/i], which are the zeroed real and imaginary parts of the complex function [b]f(z)[/b], respectively: real(f(z))=0 and imaginary(f(z))=0.[br] Point [b][color=#ff00ff]z[sub]0[/sub]' [/color][/b]of intersection of the considered curves is found ([i]using the CAS[/i]) solution of the system of two equations of these curves. The [i]starting point[/i] is the moving point [b][color=#9900ff]z[sub]0[/sub][/color][/b]. At this [i]complex point[/i], obviously, there should be f([b][color=#ff00ff]z[sub]0[/sub]'[/color][/b])=0.[br] There are 9 moving test [i]complex numbers[/i][b] [color=#ff0000]lz[/color][/b]={[color=#ff0000]z[sub]1[/sub][/color], [color=#ff0000]z[sub]2[/sub][/color],...,[color=#ff0000]z[sub]9[/sub][/color]} that can be placed "[i]approximately[/i]" at the intersection points of the considered curves. By sequentially pressing the button "SetValue[j,j+1]", these settings are refined by solving the corresponding equations in CAS. In the table you can see these 9 [i]complex numbers[/i] and see how accurate they are as the [b][i]roots[/i][/b] of the equation f([b]z[/b]). Make sure that in these cases all f[color=#ff7700](z[sub]i[/sub])[/color][color=#333333]=0[/color] are at the origin.[br] In this version of the applet (unlike the [url=https://www.geogebra.org/m/nff3yaah]previous[/url] one), the point of intersection of the curves is found by numerical methods with a high degree of accuracy.[br] More complicated view of the function is in the [url=https://www.geogebra.org/m/utjgq72u]applet[/url] .[/size]