[size=100][size=150]Consider the equation [math]q=4+0.8p[/math].[/size][br][br]What value of [math]q[/math] would make the equation true when [math]p[/math] is 7? Explain your reasoning.[/size]
[size=100]What value of [math]q[/math] would make the equation true when [math]p[/math] is 100? [size=100]Explain your reasoning.[/size][/size]
[size=100]What value of [math]p[/math] would make the equation true when [math]q[/math] is 12? [size=100]Explain your reasoning.[/size][/size]
[size=100]What value of [math]p[/math] would make the equation true when [math]q[/math] is 60? [size=100]Explain your reasoning.[/size][/size]
[size=150][list][*]Option A: [math]A\left(x\right)=60[/math][/*][*]Option B: [math]B\left(x\right)=10x+25[/math][/*][/list]In each function, the input, [math]x[/math], represents the gigabytes of data used [i]over[/i] the monthly allowance.[/size][br][br][size=100]The student decides to find the values of [math]A\left(1\right)[/math] and [math]B\left(1\right)[/math] and compare them. What are those values?[/size][br]
After looking at some of her past phone bills, she decided to compare [math]A\left(7.5\right)[/math] and [math]B\left(7.5\right)[/math]. What are those values?[br]
Describe each data plan in words.
Explain which plan you think she should choose.
The student only budgeted $50 a month for her cell phone. She thought, “I wonder how many gigabytes of data I would have for $50 if I go with Option B?” and wrote [math]B\left(x\right)=50[/math]. What is the answer to her question? Explain how you know.[br]
Describe a different data plan that, for any amount of data used, would cost no more than one of the given plans and no less than the other given plan. Explain how you know this data plan would meet these requirements.
The function [math]B[/math] is defined by the equation [math]B\left(x\right)=10x+25[/math]. [br]Use the applet below to find the value of each expression:[br][list][*][math]B(6)[/math][/*][*][math]B(2.75)[/math][/*][*][math]B(1.482)[/math][/*][/list]Use graphing technology to solve each equation:[br][list][*][math]B(x)=93[/math][/*][*][math]B(x)=42.1[/math][/*][*][math]B(x)=116.25[/math][/*][/list]