The sum of the areas of the two squares on the legs ([i]a[/i] and [i]b[/i]) equals the area of the square on the hypotenuse ([i]c[/i]).[br]
- Given a right triangle [math]\triangle ABC[/math][br]- Draw a square of size [math]a^2[/math], [math]b^2[/math] and [math]c^2[/math] on the respective sides of the triangle[br]- If you add the areas of the two small squares [math]a^2[/math] and [math]b^2[/math], you will receive the larger square, [math]c^2[/math][br]- Thus by the Pythagorean theorem the square on the side opposite the right angle equals the sum of the squares of the sides in contact with the right angle.
What are the lengths of the sides of the given right triangle?
Based on this above construction, what equation can you derive?
Based on the previous example, create the squares of the respective sides.
Mathematically show that the [math]a^2+b^2=c^2[/math] according to this triangle.
[math]8^2+6^2=64+36=100=10^2[/math]