Racionalize e simplifique a expressão:[br][br][math]\frac{4-\sqrt{6}}{\sqrt{2}}[/math]
[math]\frac{4-\sqrt{6}}{\sqrt{2}}=\frac{4-\sqrt{6}}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}\cdot\left(4-\sqrt{6}\right)}{\sqrt{4}}=\frac{4\cdot\sqrt{2}-\sqrt{12}}{2}[/math][br]Fatorando o 12 temos: [math]12=4\cdot3=2^2\cdot3[/math][br]Portanto: [math]\frac{4\sqrt{2}-\sqrt{12}}{2}=\frac{4\sqrt{2}-\sqrt{2^2\cdot3}}{2}=\frac{4\sqrt{2}-2\sqrt{3}}{2}=2\sqrt{2}-\sqrt{3}[/math]