Area of Circle

Introduction
[color=#0000ff][b][i]Area of circle is π times radius square which is written : A= π r² where,A= Area of circle and [br]r= radius of circle and π =Division of circumference and diameter ( π = 3.14159.......).[/i][/b][/color]
Objectives
[list=1][*][b][color=#ff0000]Students will be able to find the area of circle then explore the visual experience about it,[/color][/b][/*][/list]
[b][color=#0000ff]Applet[/color][/b]
Guideline
[list=1][*][i][b][color=#ff0000]To see the result click on the start button [/color][/b][/i][/*][*][i][b][color=#ff0000]To stop click on stop button and watch deeply. [/color][/b][/i][/*][/list]
Test your outstanding
Area of circle is equal to the area of ................, .
To construct area of circle by using following protocol.
[list=1][i][color=#0000ff][b][*]create slider (n,4,500,1),[/*][*]create slider (r,1,3),[/*][*]Take point A,[/*][*]Create a circle with radius 6cm and and center A,[/*][*]Create point B on the circumference,[/*][*]Input :Rotate(B, (360°) / n, A),[/*][*]join B and B',[br][/*][*]Make midpoint C of line BB',[/*][*]Join A and C,[/*][*]Rename the line BB' to dxand AC to dy,[/*][*]Input:[/*][*]L1: Sequence(Rotate(B, j (360°) / n, A), j, 0, n) ,[/*][*]L2:Sequence(CircularSector(A, Element(L1, j), Element(L1, j + 1)), j, 1, n, 2), [/*][*]L3:Sequence(CircularSector(A, Element(L1, j), Element(L1, j + 1)), j, 2, n, 2) , [/*][*]L4:Sequence(CircularSector((j dx + fdx/ 2, dy), (j dx+ 0, 0), (j dx+ dx, 0)), j, 0, n / 2 - 1),[/*][*] L5:Sequence(CircularSector((j dx, 0), (j dx + dx/ 2, dy), (j dx+ (-dx) / 2, dy)), j, 1, n / 2) [/*][*]Finally colour and design to the applet for good vidilazation.[/*][/b][/color][/i][/list]
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Information: Area of Circle