Jean Monnet HS - Hexagonal design - problem
ABCDEF is a regular hexagon with AB=2.
If G is the center of the hexagon find the area of AGB triangle.
[math]\sqrt{3}[/math]
The area of ABCDEF hexagon is:
[math]6\sqrt{3}[/math]
The yellow area is:
[math]\frac{\sqrt{3}}{2}[/math]
[math]2\sqrt{3}[/math]
[math]\sqrt{3}[/math]
[math]3[/math]
If A(0; 1) and AB||Ox The equation of the line AF is:
[math]y=\frac{-\sqrt{3}}{3}x-1[/math]
[math]y=-\sqrt{3}x-1[/math]
[math]y=x-\sqrt{3}[/math]
[math]y=\sqrt{3}x-1[/math]
The equation of the line AB is....
y=1
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Información: Jean Monnet HS - Hexagonal design - problem