Perpendicular Bisector Theorem (Part 1)

The applet below contains a segment (with endpoints A & B) and a point P that is equidistant from this segment's endpoints.
Instructions:[br][br]1) Notice how point C (in green) is the same distance (equidistant) from points A and B.[br] In fact,Point C has been programmed to always be EQUIDISTANT from the black segment's endpoints.[br][br] Use your mouse to drag point C around show show the locus (set of points) on your computer screen [br] that are equidistant from A and B. [br][br]2) What does this locus (set of points) look like? Explain.[br][br]3) Now, move point A and/or point B to change the position and length of the segment. [br] Then, click on the house button in the toolbar shown on the upper right hand side of the applet.[br] (This house button says "Back to Default View" and will erase all traces of green dots you've already made.)[br][br]4) Repeat steps (1) and (2) again, this time for this "newer" segment with endpoints A and B.[br][br]4) Click on checkbox (A) to show the locus (set of points) on your computer screen that are [br] EQUIDISTANT from A and B. [br][br]5) Use your observations to fill in each ( ) with the correct word to make a true statement: [br][br] This set of points (shown in step 4 above) looks like it is the ( ) ( ) of segment AB.[br][br]6) Click checkboxes (B) and (C) in the applet above to either check your answer to step (5) or help you fill in the [br] ( )'s for step (5).[br][br]7) Use your observations above to fill in each blank below to make a true statement: [br][br] [b]“If a point is ( ) from the ( ) of a segment, then that point[br] must lie on the ( ) ( ) of that segment.”[/b]

Information: Perpendicular Bisector Theorem (Part 1)