The equilateral triangle ABC has a side of 4 cm.[br]On the side BC, an equilateral triangle with side B'C=0.6BC is constructed. [br]The construction process continues, as in the image below.
Coordonatele punctului C sunt[br]x =...., y = ...
The ordinate of point C is found by calculating the height of the equilateral triangle.[br]The abscissa is half the abscissa of point B.
The equation of line AC is...
The equation of line BC is...
The area of the equilateral triangle with side B'C is
[math]B'C=4\cdot0.6=2.4[/math][br][math]A=\frac{^{2.4^2\sqrt{3}}}{4}=2.4\cdot0.6\sqrt{3}=14.4\sqrt{3}[/math]
What is the ratio of the areas of two consecutive triangles