Recall that, for any relation, the graph of this relation's inverse can be formed by reflecting the graph of this relation about the line y = x (Identity Function). [br][br]Recall that all functions are relations, but not all relations are functions. [br][br][br]In the applet below, you can input any function [i]f[/i] and restrict its natural domain, if you choose, to input (x) values between -10 and 10. You also have the option to graph the function over its natural domain. [br][br]Answer the next three questions then Interact with this applet for a few minutes, then complete the activity questions that follow.
What causes a relation to be a function and what causes a function to be a one to one function? Explain.
What test do we use to determine a relationship is a function graphically?
What test do we use to determine an inverse of a relationship will be a function graphically?
[color=#000000]Directions: [br][br]1) Choose the "Default to Natural Domain of f" option. [br]2) Enter in the [/color][color=#980000]original function[/color][color=#000000]. [br]3) Choose [/color][color=#38761d]"Show Inverse Relation". [/color][color=#000000]4) Is the [/color][color=#38761d]graph of this inverse relation[/color][color=#000000] the graph of a function? Explain why or why not. [br]5) If your answer to (4) above was "no", uncheck the "Default to Natural Domain of f" checkbox. [br]6) Now, can you come up with a set of Xmin and Xmax values so that the function shown has an inverse [br] that is a function? Explain. [br][br][br]Repeat steps (1) - (6) again, this time for different functions [i]f[/i] that are in our library.[br][/color]I. A linear function[br]II. A cubic function[br]III. A rational function[br]IV. A trigonometric function[br]etc.[br]
Why is the graph of y = sin(x) a function? Explain. [i]Be sure to use the terms "input" and "output" in your explanation. [/i]
Passes the vertical line test. For every input there is exactly one output.
Why is the graph of y = cos(x) a function? Explain. [i]Be sure to use the terms "input" and "output" in your explanation. [/i]
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