Parabola

Find the square function f, if [math]\text{C(3; 2)}\in G_f,D\left(2;4\right)\in G_f,E\left(0;2\right)\in G_f[/math] .

[math]\text{f(x)=-x^2+3x+2}[/math] [math]\text{f(x)=-x^2+2x-3}[/math] [math]\text{f(x)=-x^2+3x-2}[/math] [math]f\left(x\right)=-x^2-2x+3[/math]

The coordinates of the vertex of the graph of the function f are:

[math]x_V=\frac{3}{2};y_{V=}\frac{17}{6}[/math] [math]x_V=\frac{3}{2};y_{V=}\frac{17}{4}[/math] [math]x_V=\frac{3}{4};y_{V=}\frac{17}{2}[/math] [math]x_V=\frac{3}{2};y_{V=}-\frac{17}{4}[/math]

Cerrar

Parabola

Información: Parabola