[math]x+\frac{1}{2}=x-\frac{1}{2}[/math]
[math]2(x+3)=5x+6-3x[/math]
[math]3(x-5)=2(x-5)+x[/math]
[size=150]Mai says that the equation [math]2x+2=x+1[/math] has no solution because the left hand side is double the right hand side. Do you agree with Mai? Explain your reasoning.[/size]
[math]\frac{1}{2}(6x-10)-x=[/math]
[math]\frac{1}{2}(6x-10)-x=[/math]
[size=150][size=100]Here is an equation that is true for all values of [math]x[/math]: [math]5(x+2)=5x+10[/math]. Elena saw this equation and says she can tell [math]20(x+2)+31=4(5x+10)+31[/math] is also true for any value of [math]x[/math]. How can she tell? Explain your reasoning.[/size][/size]
[size=150]Elena and Lin are trying to solve [math]\frac{1}{2}x+3=\frac{7}{2}x+5[/math]. Describe the change they each make to each side of the equation.[br][br][size=100]Elena’s first step is to write [math]3=\frac{7}{2}x-\frac{1}{2}x+5[/math][/size][/size].
Lin’s first step is to write[math]x+6=7x+10.[/math]
[math]3x-6=4(2-3x)-8x[/math]
[math]\frac{1}{2}x+6=\frac{3}{2}(z+6)[/math]
[size=100][size=150]The point [math](-3,6)[/math] is on a line with a slope of 4.[/size][br][br]Find two more points on the line.[/size]
Write an equation for the line.