[size=150][b][color=#1e84cc]Is the preimage (AB) Daffy congruent with the image (A[/color][/b][math]'[/math][b][color=#1e84cc]B[/color][/b][math]'[/math][b][color=#1e84cc])Daffy?[/color][/b] [/size]
Yes, each point reflected over CD is an equal, but opposite distance from the reflection line (CD). If you were able to pick up the image Daffy, turn in over and place it on top of preimage Daffy, the images would map onto each other.