(c) Is AEBD a parallelogram? rectangle? rhombus? square? Explain your reasoning.[br][br]Hint: Remember the Parallelogram Diagonals Converse (Thm. 7.10).[br]
yes; no; yes; no; Because the[br]diagonals bisect each other,[br][i]AEBD[/i] is a parallelogram by[br]the Parallelogram Diagonals[br]Converse (Thm. 7.10). Because[br][i]EB = BD = AD = AE[/i], [i]AEBD[/i][br]is a rhombus. [i]AEBD[/i] is neither a[br]rectangle nor a square because its[br]angles are not necessarily right[br]angles.