Con riferimento ai post: [url]http://www.geogebra.org/forum/viewtopic.php?f=2&t=38591&hilit=alfabeta&%20id=3820274eb4522211dec053f33914ff8b[/url] e [url]http://www.geogebra.org/forum/viewtopic.php?f=10&t=38959&hilit=bisettrici&sid=33ee587279f901ea3ea8c6946c59ba13[/url] credo (?) di aver trovato la soluzione al problema proposto:Given a triangle ABC (AB=2 , AC=3 and BC=4 ) formed by the foot of the angle bisectors of triangle A'B'C' where A is opposite A', B is opposite B', and C is opposite C'. How do you construct triangle A'B'C'?
